SQL Server 获取表结构中字段的备注、主键等信息的sql

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1、MSSQL2000

代码如下:

 
SELECT 
表名 = case when a.colorder=1 then d.name else '' end, 
表说明 = case when a.colorder=1 then isnull(f.value,'') else '' end, 
字段序号 = a.colorder, 
字段名 = a.name, 
标识 = case when COLUMNPROPERTY( a.id,a.name,'IsIdentity')=1 then '√'else '' end, 
主键 = case when exists(SELECT 1 FROM sysobjects where xtype='PK' and parent_obj=a.id and name in ( 
SELECT name FROM sysindexes WHERE indid in( 
SELECT indid FROM sysindexkeys WHERE id = a.id AND colid=a.colid))) then '√' else '' end, 
类型 = b.name, 
占用字节数 = a.length, 
长度 = COLUMNPROPERTY(a.id,a.name,'PRECISION'), 
小数位数 = isnull(COLUMNPROPERTY(a.id,a.name,'Scale'),0), 
允许空 = case when a.isnullable=1 then '√'else '' end, 
默认值 = isnull(e.text,''), 
字段说明 = isnull(g.[value],'') 
FROM 
syscolumns a 
left join 
systypes b 
on 
a.xusertype=b.xusertype 
inner join 
sysobjects d 
on 
a.id=d.id and d.xtype='U' and d.name<>'dtproperties' 
left join 
syscomments e 
on 
a.cdefault=e.id 
left join 
sysproperties g 
on 
a.id=g.id and a.colid=g.smallid 
left join 
sysproperties f 
on 
d.id=f.id and f.smallid=0 
where 
d.name='FI_dept' --如果只查询指定表,加上此条件 
order by 

a.id,a.colorder 

2、MSSQL2005

use test--数据库
go
--2005实现字段属性统计(2000里的系统表sysproperties描述表、字段不存在，2005里用sys.extended_properties视图替代)
select
[表名]=c.Name,
[表说明]=isnull(f.[value],''),
[列名]=a.Name,
[列序号]=a.Column_id,
[标识]=case when is_identity=1 then '√' else '' end,
[主键]=case when exists(select 1 from sys.objects where parent_object_id=a.object_id and type=N'PK' and name in
(select Name from sys.indexes where index_id in
(select indid from sysindexkeys where and colid=a.column_id)))
then '√' else '' end,
[类型]=b.Name,
[字节数]=case when a.[max_length]=-1 and b.Name!='xml' then 'max/2G'
when b.Name='xml' then ' 2^31-1字节/2G'
else rtrim(a.[max_length]) end,
[长度]=ColumnProperty(a.object_id,a.Name,'Precision'),
[小数]=isnull(ColumnProperty(a.object_id,a.Name,'Scale'),0),
[是否為空]=case when a.is_nullable=1 then '√' else '' end,
[列说明]=isnull(e.[value],''),
[默认值]=isnull(d.text,'')
from
sys.columns a
left join
sys.types b on a.user_type_id=b.user_type_id
inner join
sys.objects c on a.object_id=c.object_id and c.Type='U'
left join
syscomments d on a.default_object_id=d.ID
left join
sys.extended_properties e on e.major_id=c.object_id and e.minor_id=a.Column_id and e.class=1
left join
sys.extended_properties f on f.major_id=c.object_id and f.minor_id=0 and f.class=1
[/code]
结果：
【图片暂缺】

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