这篇文章主要为大家详细介绍了SQL Server SQL 判断给定日期值(或时间段)所在星期的星期一和星期天的日期,具有一定的参考价值,可以用来参考一下。
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一、给定一个日期值,求出此日期所在星期的星期一和星期天的日期数据代码如下:
USE [MSSQL]
GO
SET ANSI_NULLS ON
GO
SET QUOTED_IDENTIFIER ON
GO
CREATE FUNCTION [dbo].[My_OneDay_GetWeekFirstAndEndDay](@tmpDate DATETIME)
RETURNS @tmpTable TABLE(FirstDay DATETIME , EndDay DATETIME)
AS
BEGIN
INSERT INTO @tmpTable
SELECT a.FirstDay,b.EndDay FROM (
SELECT 1 AS ID,DATEADD(wk, DATEDIFF(wk,0,@tmpDate), 0) AS FirstDAy
) a
LEFT JOIN (
SELECT 1 AS ID,DATEADD(wk, DATEDIFF(wk,0,@tmpDate), 6) AS EndDay
) b
ON a.ID = b.ID
RETURN
End
代码如下:
SELECT * from My_OneDay_GetWeekFirstAndEndDay('2010-09-01')
代码如下:
USE [MSSQL]
GO
SET ANSI_NULLS ON
GO
SET QUOTED_IDENTIFIER ON
GO
CREATE FUNCTION [dbo].[MY_Range_GetWeekFirstAndEndDays](@tmpDateSTART DATETIME,@tmpDateEND DATETIME)
RETURNS @tmpTable TABLE(WeekOrder INT,FirstDay DATETIME , EndDay DATETIME)
AS
BEGIN
DECLARE @tmpDate DATETIME
DECLARE @index INT
SET @tmpDate=@tmpDateSTART
SET @index=1
WHILE @tmpDate <=@tmpDateEND
BEGIN
INSERT INTO @tmpTable
SELECT @index,a.FirstDay,b.EndDay FROM (
SELECT 1 AS ID,DATEADD(wk, DATEDIFF(wk,0,@tmpDate), 0) AS FirstDAy) a
LEFT JOIN (
SELECT 1 AS ID,DATEADD(wk, DATEDIFF(wk,0,@tmpDate), 6) AS EndDay) b
ON a.ID = b.ID
SET @tmpDate=DATEADD(DAY,7,@tmpDate)
SET @index=@index+1
END
RETURN
End
代码如下:
SELECT * from My_Range_GetWeekFirstAndEndDays('2011-09-01','2011-10-06')
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关键词:SQL SERVER
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